Differential equation right hand function

Doubell
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Homework Statement


The question specifies the auxiliary equation given is (D^2 + D - 2) = (e^x)/(x)
the method of variation of parameter must be used to find the particular solution to the right hand function. then finally the general soultion should be stated.

Homework Equations


variation of paremeters formula.
yp = -y1∫y2 * g(x)/ (w(y1 , y2))
+ y2∫y1 * g(x)/ (w(y1 , y2))

The Attempt at a Solution


i had solved the complementary function and had gotten yc = c1e-x + c2e-2x. then after applying the formula for variation of parameters i had gotten e-x*lnx/3 - e-2x/3 * ∫e3x / x
i cannot obtain an integral for ∫e3x / x i don't think it can be done have tried various mathods eg by parts, there are no suitable substitutions is it that there is no integral for the expression? i.e. it cannot be integrated.
 
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Doubell said:

Homework Statement


The question specifies the auxiliary equation given is (D^2 + D - 2) = (e^x)/(x)
the method of variation of parameter must be used to find the particular solution to the right hand function. then finally the general soultion should be stated.


Homework Equations


variation of paremeters formula.
yp = -y1∫y2 * g(x)/ (w(y11 , y2))
+ y2∫y1 * g(x)/ (w(y11 , y2))

The Attempt at a Solution


i had solved the complementary function and had gotten yc = c1e-x + c2e-2x. then after applying the formula for variation of parameters i had gotten e-x*lnx/3 - e-2x/3 * ∫e3x / x
i cannot obtain an integral for ∫e3x / x i don't think it can be done have tried various mathods eg by parts, there are no suitable substitutions is it that there is no integral for the expression? i.e. it cannot be integrated.

I haven't worked through this problem, but you are correct that ##\frac {e^{3x}} x## does not have an elementary antiderivative.
 
Doubell said:

Homework Statement


The question specifies the auxiliary equation given is (D^2 + D - 2) = (e^x)/(x)
the method of variation of parameter must be used to find the particular solution to the right hand function. then finally the general soultion should be stated.


Homework Equations


variation of paremeters formula.
yp = -y1∫y2 * g(x)/ (w(y1 , y2))
+ y2∫y1 * g(x)/ (w(y1 , y2))

The Attempt at a Solution


i had solved the complementary function and had gotten yc = c1e-x + c2e-2x.
You have a mistake. What you have as e-x should be e+x. The other one is fine.
Doubell said:
then after applying the formula for variation of parameters i had gotten e-x*lnx/3 - e-2x/3 * ∫e3x / x
i cannot obtain an integral for ∫e3x / x i don't think it can be done have tried various mathods eg by parts, there are no suitable substitutions is it that there is no integral for the expression? i.e. it cannot be integrated.
 
Mark44 said:
You have a mistake. What you have as e-x should be e+x. The other one is fine.
yes it is as u say but the problem still remains the same the∫e3x/x would still have to be determined
 
Doubell said:
yes it is as u say but the problem still remains the same the∫e3x/x would still have to be determined
But if you have an incorrect function in your variation of parameters formula, you'll definitely get the wrong answer.

Also, "textspeak" (such as "u" for "you") isn't permitted here at PF.

Please show your work in this formula:
Doubell said:
yp = -y1∫y2 * g(x)/ (w(y1 , y2))
+ y2∫y1 * g(x)/ (w(y1 , y2))
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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