Differential Equations: Non-homogeneous Series Expansion

Bryon
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Homework Statement



y'' + y' + y = 1 + x + x2

Homework Equations



y = Ʃ CN*xN N starts at 0
y' = Ʃ N*CN*x(N-1) N starts at 1
y'' = Ʃ N*(N-1)*CN*x(N-2) N starts at 2

3. The Attempt at a Solution [/]
I know how solve the equations using series when the equation would equal to 0. My main question about using series on a non-homogeneous differential equation is whether or not the varialbes on the right side have the Cx coefficients? Or would they be paired up with the x, x2, etc? I think I need some quick clarification on this.

Thanks!
 
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Bryon said:

Homework Statement



y'' + y' + y = 1 + x + x2

Homework Equations



y = Ʃ CN*xN N starts at 0
y' = Ʃ N*CN*x(N-1) N starts at 1
y'' = Ʃ N*(N-1)*CN*x(N-2) N starts at 2

3. The Attempt at a Solution [/]
I know how solve the equations using series when the equation would equal to 0. My main question about using series on a non-homogeneous differential equation is whether or not the varialbes on the right side have the Cx coefficients? Or would they be paired up with the x, x2, etc? I think I need some quick clarification on this.

Thanks!


The Cn's only appear in your expressions for y and its derivatives. But you must take the powers of x on the other side into account for your recursion formulas. I assume you know that series isn't the easiest way for this problem.
 
Thanks for clearing that up. The instructor covered only homogenous problems, and when I ran into one of these I was not entirely sure how to solve it with series.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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