Differential equations power series method

SpiffyEh
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Homework Statement



using the power series method (centered at t=0) y'+t^3y = 0 find the recurrence relation

Homework Equations



y= \sum a_{n}t^{n} from n=0 to infinity
y'= \sum na_{n}t^{n-1} from n=1 to infinity

The Attempt at a Solution


I went through and solved by putting the values from b into the equation and i got down to this:
a_{1}+2a_{2}t+3a_{3}t^{2}+\sum[na_{n}+a_{n-4}]t^{n-1} = 0

the 1 2 and 3 should be subscripted on a

I understand how to get an which i think i got right... i got a_{n} = -a_{n-4}/n whre n >= 4

But I don't understand what i do with the other part.. the a_{1}+2a_{2}t+3a_{3}t^{2}
Do i set it to 0 and solve for something? or do i set each individual component to 0. If i do ti this way and i find the power series solution by going through values of n until i find a pattern they all end up being 0 which can't be right. I'm completely lost.

Please let me know, this is due tomorrow and I have everything done except I don't understand what to do with this one. I just need to know what to do with that part, I can do the rest.

Thank you so much
 
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SpiffyEh said:

Homework Statement



using the power series method (centered at t=0) y'+t^3y = 0 find the recurrence relation

Homework Equations



y= \sum a_{n}t^{n} from n=0 to infinity
y'= \sum na_{n}t^{n-1} from n=1 to infinity

The Attempt at a Solution


I went through and solved by putting the values from b into the equation and i got down to this:
a_{1}+2a_{2}t+3a_{3}t^{2}+\sum[na_{n}+a_{n-4}]t^{n-1} = 0

the 1 2 and 3 should be subscripted on a

I understand how to get an which i think i got right... i got a_{n} = -a_{n-4}/n whre n >= 4

But I don't understand what i do with the other part.. the a_{1}+2a_{2}t+3a_{3}t^{2}
Do i set it to 0 and solve for something? or do i set each individual component to 0. If i do ti this way and i find the power series solution by going through values of n until i find a pattern they all end up being 0 which can't be right. I'm completely lost.

Please let me know, this is due tomorrow and I have everything done except I don't understand what to do with this one. I just need to know what to do with that part, I can do the rest.

Thank you so much
You're right. You set the first three terms to zero, so you get a_1=a_2=a_3=0. The only non-zero terms in your power series will therefore be for n=0, 4, 8, ...

This differential equation is separable, so you can find the solution in closed form. Expand it as a series and see if it matches what the series solution seems to be giving you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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