Differential forms and visualizing them

[Storm Butler]

I made a post titled the same thing but it didnt seem to show up for some reason so if i am just reposting this over again i apologize.

I recently got the book A geometrical approach to differential forms by David Bachman. At the moment the biggest issue i am having is just visualizing what the form should look like/ be. The calculations for a one form and a vector are pretty much the same for a dot product so should the form be visualized as a vector? if so where is it and why does it have such an odd notation if it can't be visualized as a vector then how should we (I) picture it?

Thanks for any help you can give me

 

[HallsofIvy]

I think you will find it helpful to think in terms of "linear functionals". A linear functional is a linear transformation that maps a vector into a real number. One thing that can be shown is that, given a vector space, V, the set of all linear functionals from V to the real numbers is itself a vector space where, if f and g are linear functionals, a, b numbers, af+ bg is defined as the linear functional that maps v to af(v)+ bg(v).

If V has finite dimension n, then the set of linear functions, V*, has dimension n also and there is a one to one correspondence. Choosing basis for V, through that correspondence, automatically assigns a basis to V*. Specifically, if \{v_1, v_2, ..., v_n\} is a basis for v, then the set of linear functionals, \{f_1, f_2, ..., f_n\} where f_k is defined by "f_k(v_k)= 1, f_k(v_i)= 0 if i\ne k and extended to all vectors by "linearity"- if v= a_1v_1+ a_2v_2+ ...+ a_nv_n then the functional corresponding to v is f_v= a_1f_{v_1}+ a_2f_{v_2}+ ... + a_nf_{v_n}.

Now, a more formal definition of "dot product" would be [math]v\cdot u= f_v(u)[/math] where [math]f_v[/math] is the linear functional corresponding to v.

The purpose of all that is to say that we can think of differential forms in exactly the same way- they are "functionals that assign numbers to functions (vectors)":
The differential form d\mu assigns, to each function, x, \int f d\mu.