Differentiation under the integral

In summary, the conversation is about finding the function f(\alpha) through differentiation and integration, with the goal of getting a factor of pi in the answer. The conversation also mentions the use of a substitution and clarifies the relationship between log(1+acos(x)) and cos(x)/(1+acos(x)).
  • #1
ehrenfest
2,020
1

Homework Statement


[tex] f(\alpha) = \int \log(1+ \alpha \cos(x))dx [/tex]

I am supposed to differentiate w.r.t alpha and then integrate to find f(alpha).

My book says that there should be a factor of pi in the answer but I do not get one. Does anyone else?

Homework Equations


The Attempt at a Solution

 
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  • #2
no bounds to that integral?
 
  • #3
Sorry. It goes from 0 to pi.
 
  • #4
Okay, so we differentiate:
[tex]f'(\alpha)=\int_{0}^{\pi}\frac{\cos(x)}{1+\alpha\cos(x)}dx=\frac{1}{\alpha}\int_{0}^{\pi}(1-\frac{1}{1+\alpha\cos(x)})dx,f(0)=0[/tex]
See if this brings you any further.

The substitution [tex]u=\tan(\frac{x}{2})[/tex] might well be helpful.
 
  • #5
is log(1+acos(x)) = cos(x)/(1+acos(x)) ?
 
  • #6
No, he was doing what the thread title says. It's the derivative of your integrand with respect to alpha.
 

1. What is differentiation under the integral?

Differentiation under the integral, also known as the Leibniz integral rule, is a method for calculating the derivative of a function that is defined by an integral. It allows us to differentiate a function with respect to a variable that is both inside and outside the integral.

2. When is differentiation under the integral used?

Differentiation under the integral is used when the function to be differentiated cannot be expressed in terms of elementary functions, making traditional differentiation methods difficult or impossible to use. It is also used in applications such as physics, engineering, and economics, where integrals are commonly used to model real-world problems.

3. How does differentiation under the integral work?

The Leibniz integral rule states that the derivative of a function defined by an integral is equal to the integral of the derivative of the function with respect to the variable of integration. This means that we can differentiate the integrand (the function inside the integral) as if the variable of integration were a constant, and then integrate the resulting expression with respect to the original variable.

4. Are there any limitations to differentiation under the integral?

While differentiation under the integral is a powerful tool, it does have some limitations. It can only be used when the function to be differentiated is continuous and the integral exists. It also cannot be used if the integrand depends on the variable of integration in a non-differentiable way, such as through a discontinuity or a singularity.

5. Can differentiation under the integral be extended to multiple variables?

Yes, the Leibniz integral rule can be extended to multiple variables, known as the multivariate Leibniz integral rule. It allows us to differentiate a function with respect to multiple variables that are both inside and outside the integral. This is useful in higher-dimensional applications such as vector calculus and partial differential equations.

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