Tom83B
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This is in my book:
exp[2\pi i(hx+ky+lz)][1+exp(\pi i(h+k+l))]=2exp[2\pi i(hx+ky+lz)]\cos^2[\frac{\pi}{2}(h+k+l)]
And in order for the cosine not to be zero, h+k+l must be even when we want to see the reflection.
But I think that the result should be exp[2\pi i(hx+ky+lz)](2\cos^2[\frac{\pi}{2}(h+k+l)]+i\sin[\pi(h+k+l)])
Why isn't the imaginary part there? My idea was that we only need the real part, but because we multiply two complex numbers, I can't do this because i^2=-1, can I?
exp[2\pi i(hx+ky+lz)][1+exp(\pi i(h+k+l))]=2exp[2\pi i(hx+ky+lz)]\cos^2[\frac{\pi}{2}(h+k+l)]
And in order for the cosine not to be zero, h+k+l must be even when we want to see the reflection.
But I think that the result should be exp[2\pi i(hx+ky+lz)](2\cos^2[\frac{\pi}{2}(h+k+l)]+i\sin[\pi(h+k+l)])
Why isn't the imaginary part there? My idea was that we only need the real part, but because we multiply two complex numbers, I can't do this because i^2=-1, can I?