Is the Velocity Equation v^2 = v0^2 + 2ax Dimensionally Correct?

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The discussion revolves around verifying the dimensional correctness of the equation v^2 = v0^2 + 2ax, where v and v0 are velocities, a is acceleration, and x is distance. The initial attempt to demonstrate this involved expressing the dimensions of v^2 and 2ax. It was clarified that the dimensions of 2ax can be calculated as (L/T²)(L), resulting in L²/T², which matches the dimensions of (L/T)² for v^2. This confirms that the equation is dimensionally correct. The conversation emphasizes the importance of detailed dimensional analysis in physics.
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Hello physicists!
I'm taking a physics class and I'm in need of some assistance. I'm just starting out, so bear with me. The question I'm confused about is probably quite simple and I'm just not getting it..


q. Show that the equation v^2 = v0^2 + 2ax is dimensionally correct, where v and v0 represent velocities, a is acceleration and x is distance.

a. i said:

v^2 = v0^2 = (L/T)^2
2ax = 2(L/T)^2

Any assistance would be greatly appreciated. Thanks !
 
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Welcome to Physics Forums, Skippinrocks.

It says "show that", so you should probably show a little more detail in the second part:
2ax has dimensions (L/T²)(L) = L²/T² = (L/T)²
 

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