Diode Equation and Saturation Current

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DeldotB
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Good day all:

For the diode equation: [tex]I(V)=I_{sat}e^{\frac{Ve}{nKT}}-I_{sat}[/tex]

I also know that the second term in the equation is negligible if: [tex]V> > nV_{T}[/tex]

Vt is thermal voltage
n is ...just a factor related to the quality of the material

I have these initial conditions:
[tex]V> 0.1V\, \, \, ,kT\approx .025 eV\, \, \, n\approx 2[/tex]

Its easy to show that the my inital conditions lead to a V much greater that n*thermal voltage.

My question is: Why is the saturation Current negligible? I know it has something to do with recombination rate but can anyone give me a simple explanation? So many websites just say that the order relation is true but give no evidence as to why.
 
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In forward bias, the Is component is tiny. You only see it in reverse bias before avalanche breakdown...

http://www.electrotechservices.com/electronics/images/diode_graph.jpg
diode_graph.jpg

Does that help?
 
Because most of the current is in the forward direction and the reverse current, due to the minority carriers, is low. Typically in the order of nA to uA.