- #1

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I am having difficulty interpreting M(x,x') into dirac notation. How do i write M(x,x') in dirac notation? The actual problem is to write the following in dirac notation:

int { int { m(x)* M(x,x') g(x') } dx} dx'

I would appreciate your help.

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- Thread starter raj2004
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- #1

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I am having difficulty interpreting M(x,x') into dirac notation. How do i write M(x,x') in dirac notation? The actual problem is to write the following in dirac notation:

int { int { m(x)* M(x,x') g(x') } dx} dx'

I would appreciate your help.

- #2

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Hey guys,

I am having difficulty interpreting M(x,x') into dirac notation. How do i write M(x,x') in dirac notation? The actual problem is to write the following in dirac notation:

I would appreciate your help.

int { int { m(x)* M(x,x') g(x') } dx} dx'

i tried to use M(x,x') = m(x) m(x'). would that be appropriate?

- #3

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could any one help me on this ?

- #4

mjsd

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what is what in

?int { int { m(x)* M(x,x') g(x') } dx} dx'

- #5

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int means integration

- #6

mjsd

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and what about m , M, g? are the states, operators .. what is what?

- #7

CompuChip

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- #8

CompuChip

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For your attempt at solution, I don't know what M and m are supposed to be, but if they are what I think they are (M is some sort of propagator and m is a state) then I don't think you can write this.

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- #10

CompuChip

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Have you tried that already?

- #11

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- #12

malawi_glenn

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- #13

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- #14

CompuChip

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OK, let me put it this way: do you know what [itex]\int \mathrm{d}x |x\rangle\langle x|[/itex] is?

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