(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The x component of vector is -16.2 m and the y component is +54.6 m. (a) What is the magnitude of ? (b) What is the angle (in radians) between the direction of and the positive direction of x?

2. Relevant equations

magnitude of vector is sqrt of a^2+b^2

direction of vector is tan theta= ay/ax

3. The attempt at a solution

I got A part correct by finding the magnitude using sqrt of a^2+b^2= 56.95m but i can't seem to get b part. i did inverse tan of 56.4m/-16.2m and got -1.28 radians and its wrong. HELP!!!

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# Homework Help: Direction of a vector after I have already found magnitude

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