Discover the Properties of an Image in a Concave Mirror | 50 cm Focal Length

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To determine the properties of an image formed by a concave mirror with a 50 cm focal length, the mirror equation (1/image distance + 1/object distance = 1/focal length) and the magnification equation (m = image size / object size) are essential. The object is placed 1.5 m from the mirror, and its height is 2.5 cm. A diagram is recommended to correctly apply the sign convention and visualize the image orientation. Experimenting with a spoon can help clarify the image's orientation. Understanding these equations and concepts is crucial for solving the problem effectively.
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20. Using the mirror equation and the magnification equation, find the four properties of the image formed in a concave mirror with a focal length of 50 cm, if the object is 1.5 m from the mirror and is 2.5 cm high.


Can anyone tell me the mirror equation and magnification equation and how to apply to this problem please?... Thankyou
 
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Mirror equation is
1/image distance + 1/object distance = 1/focal length

magnification equation is
m = image size / object size

Draw a diagram or you will never get the sign convention right - hint experiment with a spoon to work out which way up the image should be.
 
thankyou
 

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