Discover the Tangential Velocity for the Wall of Death Amusement Park Ride

AI Thread Summary
The Wall of Death ride operates by spinning a vertical cylinder, allowing riders to remain against the wall due to friction when the floor drops away. The radius of the cylinder is 3.9 meters, and the coefficient of static friction is 0.35. To prevent riders from slipping, the necessary centripetal acceleration is calculated as 3.43 m/s², derived from the frictional force equating to the weight of the riders. The discussion emphasizes the relationship between centripetal force and normal reaction, guiding the calculation of minimum tangential velocity. Understanding these dynamics is crucial for ensuring rider safety on the attraction.
am08
Messages
43
Reaction score
0
The Wall of Death in an amusement park is comprised of a vertical cylinder that can spin around the vertical axis. Riders stand against the wall of the spinning cylinder and the floor falls away leaving the riders held up by friction. The radius of the cylinder is 3.9 m and the coefficent of static friction between the rider and the wall is 0.35. Find the tangential velocity of the spinning wall necessary so that the riders do not slip down the wall.

Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How do I apply that to find the tangential velocity?
 
Physics news on Phys.org
am08 said:
Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How did you get this??

Centripetal force is the normal reaction N. The frictional force F must be equal to weight. You should know the relationship between F and N when static friction is max. Now write the correct eqn for minimum tangential velocity.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Help Solve Amusement Park Wall of Death Problem
Replies
2
Views
5K
Force at the Bottom of a Circular Amusement Park Ride
Replies
3
Views
2K
Friction, centripetal force, gravity, and velocity
Replies
1
Views
2K
Wall of Death in amusement park - Find number of revolutions
Replies
3
Views
4K
Centripetal Force of an amusement park ride
Replies
6
Views
5K
Tangential, Radial and total acceleration
Replies
1
Views
2K
Amusement Rotor Ride Explanation
Replies
6
Views
10K
Circular Motion -> amusement park ride
Replies
3
Views
11K
Centripetal Motion Homework: Min Coeff of Friction
Replies
2
Views
2K
Nonuniform Circular Motion: Old-Fashioned Amusement Park Ride
Replies
2
Views
6K

Hot Threads

Recent Insights

Back
Top