Discovering the Maximum Force to Keep a Box at Rest on an Inclined Ramp

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To determine the maximum force that can keep a 22 kg box at rest on a 45-degree inclined ramp, the equations of motion need to be correctly set up. The normal force (Fn) is influenced by the gravitational force (Fgy) and the applied force (Fapp), while the net force (Fnet) must equal zero for the box to remain stationary. The frictional force (Ffs) acts against the direction of potential motion, which is crucial for calculating the applied force. Clarification is needed on the definitions of Fn, Fapp, and Ffs, as well as the direction of friction to resolve the negative value issue encountered in the calculations. Understanding these concepts is essential for correctly solving the problem.
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This question is driving me nuts. I really need help with it, actually i just need help setting up my equations.

Mu = the weird friction sympol

A box of a mass m=22 kg is at rest on a ramp inclined at 45 degrees to the horizontal. The coefficient of friction between the box and the ramp are "Mu s" = 0.78 and "Mu k" = 0.65.
a)Determine the magnitude of the largest force that can be applied upward, parallel to the ramp, if the box is to remain at rest.

My equation are:

Fn=Fgy - Fapp
Fnet = 0
also
Fnet = Fgx - Ffs

After that i end up getting two equations for Fapp but when i solve for it i get a negative answer. I also tried flipping Fapp so Fn=Fapp - Fgy but that also won't work, i get the wrong answer.

So can anyone please help get my two equations, there's something wrong with mine.
 
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Please clarify your expressions, what is Fn, what are Fapp and Ffs?

Which way does the friction act?
 

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