- #1
mhill
- 189
- 1
discrete spacetime means discrete momentum ??
the question is using De Broglie's Wavelength [tex] \lambda = h|p|^{-1} [/tex]
then in case space is discrete would mean that there is a minimum possible wavelength in nature , for example [tex] \lambda = k l_{p} [/tex] for Planck's length this would mean that the maximum allowed momentum modulus would be [tex] h(k l_{p})^{-1} [/tex] for 'k' a constant , then since momentum is finite and spacetime is also finite there wouldn't be any IR or UV divergences but does this make sense
the question is using De Broglie's Wavelength [tex] \lambda = h|p|^{-1} [/tex]
then in case space is discrete would mean that there is a minimum possible wavelength in nature , for example [tex] \lambda = k l_{p} [/tex] for Planck's length this would mean that the maximum allowed momentum modulus would be [tex] h(k l_{p})^{-1} [/tex] for 'k' a constant , then since momentum is finite and spacetime is also finite there wouldn't be any IR or UV divergences but does this make sense