Dissipation of Power by Resistors

AI Thread Summary
The discussion focuses on calculating the power dissipated by resistors using the formulas P=IV and P=I²R. The user initially misapplied the total voltage across individual resistors instead of calculating the current through them. After clarification, the correct approach involves finding the total resistance and current before applying the power formula for each resistor. The calculations provided show the power dissipated by each resistor, with PR1 yielding 48/25 and PR2 yielding 72/25. The thread concludes with a confirmation of the correct method and results.
cwesto
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Homework Statement



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Homework Equations



P=IV
I=V/R
P=(V/R)V
R=V2/R

The Attempt at a Solution



PR1: 122/12=12
PR2: 144/18

I'm not sure what to do from here. Thanks for any input and help!
 
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Maybe start with how much current is passing through the resistors?

Your attempt incorrectly tried to use the total Voltage of the supply across the resistors singly. The question wants to know the power dissipated by each resistor.

Once you have the current then won't the power for any resistor be P = I2R ?
 
I=V/R
Rtotal=12+18
I=12/30
PR1=RI2
PR1=12*\frac{2}{5}*\frac{2}{5}
PR1=48/25

PR2=\frac{72}{25}=2.88
Thanks!
 
cwesto said:
I=V/R
Rtotal=12+18
I=12/30
PR1=RI2
PR1=12*\frac{2}{5}*\frac{2}{5}
PR1=48/25

PR2=\frac{72}{25}=2.88
Thanks!

There you go. Good job.
 
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