(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

L1 L2

x= 1+t x= 1+2s

y= 1+6t y= 5+15s

z= 2t z= -2+6s

My professor said to find a normal vector and project the lines, but I'm new to this calculus and all these words are just a fuzzy cloud over my head.

2. Relevant equations

Projection of c onto L1 -> (C dot L1 / magnitude C) (L1 / magnitude L1)

Or (C dot L1)C/(magnitude C^2)

3. The attempt at a solution

L1xL2= a vector of <6,2,3> = C

The direction vector for L1 = <1,6,2>

L2 = <2,15,6>

So I think I need to project one onto the other....

But when I do that I get another vector, that's <144/7,48/7,72/7>. Do I find the magnitude of this, and that should be the distance? I'm lost. The magnitude of that vector is 24, which is a clean answer so it could be right.....

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# Homework Help: Distance between two skew lines given by parametric equations (and more!)

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