Distance to an ellipse surface

In summary, the conversation discusses a path planning algorithm using potential flows to guide a non-holonomic robot through a field of obstacles. The issue at hand is calculating the distance to the surface of an elliptical obstacle, which is currently done through an inefficient and slow method. The speaker is seeking a mathematical equation or geometric technique to easily find the shortest distance to an ellipse from a point in space. The conversation ends with a suggestion to use a computer algebra system to calculate the derivative in order to find the optimal distance.
  • #1
Trenthan
54
0
Hey guys, this isn't a course work question more independent study to improve something I'm working on for my course, to increase computation time.

It may be in the wrong thread but the others state to post independent study in the homework section so its here. Placed it in maths since its seems most relevant but please feel free to move this thread if its in the wrong place!

Bit of background first
-I'm currently producing a path planning algorithm using potential flows to guide a non-holonomic robot through a field of obstacles.
-To model multiple obstacles we use a weighting function that determines which object is dodged first, and is dependent on the DISTANCE to the SURFACE of THAT OBSTACLE from our robots position in the field.

Now everything works fine, and i can produce smooth trajectories around multiple obstacles in a large field.

Issue is calculating the distance to the surface of an elliptical obstacle and plates (lets ignore plates for now).

This is currently done by generating the coordinates of the ellipse surface, and by searching for the smallest distance between the surface coordinate and robot position. Right away you can see this is inefficient and slow!

It works in real time since its generated step by step while the robot moves, but for simulation purposes its too slow. If it takes the robot in reality 20seconds to trace the path, its takes 20 seconds to generate the simulation for a fake environment of the computer. (if its 2 minutes, than its 2 minutes as well). This makes it difficult when coding and playing around with ideas since i loose a lot of time sitting around waiting to see the result. This section of the code takes up 95% of the computation time so if it can be reduced, it would be a big plus!

I'm curious to know if there is a neat mathematical equation, or some geometric techniques that can easily allow me to find the shortest distance to an ellipse from a point in space**. (If it could be done with the ellipse at any orientation (45, 217 degrees etc) it would be better, but i can easily address this with other algorithms currently implemented).

Im happy to be pointed in the correct direction, I've hunted IEEE, gone through my old course work and nothing on this type of stuff. Searched the web without much luck; more a lot of junk that isn't too useful.

Cheers Trent
 
Physics news on Phys.org
  • #2
Hi Trenthan! :smile:

Let's get you on the way. The general equation for an ellipse is

[tex]\left\{\begin{array}{c}
x=x_c+a\cos(t)\cos(\varphi)-b\sin(t)\sin(\varphi)\\
y=y_c+a\cos(t)\sin(\varphi)+b\sin(t)\cos(\varphi)\\
\end{array}\right.[/tex]

where [itex](x_c,y_c)[/itex] is the origin of the ellipse, where a and b describe the length of the major and minor axis and where [itex]\varphi[/itex] is the anlge of the major axis with the x-axis.

Let [itex](x_0,y_0)[/itex] be the point in space. Your job is now to minimize

[tex]\sqrt{(x_c+a\cos(t)\cos(\varphi)-b\sin(t)\sin(\varphi)-x_0)^2 + (y_c+a\cos(t)\sin(\varphi)+b\sin(t)\cos(\varphi)-y_0)^2}[/tex]

with respect to t. I.e. you need to find the t that makes the above expression minimal. OF course, the square root can be dropped, so you need to find the t that minimizes

[tex](x_c+a\cos(t)\cos(\varphi)-b\sin(t)\sin(\varphi)-x_0)^2 + (y_c+a\cos(t)\sin(\varphi)+b\sin(t)\cos(\varphi)-y_0)^2[/tex]

To do this, calculate the derivative of this expression and see when it equals 0. You may want to use a computer algebra system for that like wolfram alpha...
 

1. What is the distance to an ellipse surface?

The distance to an ellipse surface is the shortest distance from a point to the surface of an ellipse. It is often referred to as the "perpendicular distance" or "normal distance".

2. How is the distance to an ellipse surface calculated?

The distance to an ellipse surface can be calculated using the formula d = |Ax + By + C| / √(A^2 + B^2), where A, B, and C are constants that represent the coefficients of the equation of the ellipse, and x and y are the coordinates of the point.

3. Can the distance to an ellipse surface be negative?

Yes, the distance to an ellipse surface can be negative if the point is inside the ellipse. In this case, the distance is measured in the opposite direction of the normal vector to the surface.

4. How does the distance to an ellipse surface relate to the eccentricity of the ellipse?

The distance to an ellipse surface is directly related to the eccentricity of the ellipse. The higher the eccentricity, the more elongated the ellipse is, and the greater the distance from the center to the surface will be.

5. Is the distance to an ellipse surface the same as the distance to its foci?

No, the distance to an ellipse surface and the distance to its foci are not the same. The distance to an ellipse surface is the shortest distance from a point to the surface of the ellipse, while the distance to its foci is the distance from a point to the two focal points of the ellipse.

Similar threads

Replies
6
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
18
Views
1K
Replies
3
Views
817
Replies
15
Views
2K
  • Introductory Physics Homework Help
Replies
21
Views
667
  • Calculus and Beyond Homework Help
Replies
11
Views
2K
Replies
1
Views
2K
Replies
4
Views
737
  • Sci-Fi Writing and World Building
Replies
13
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
1K
Back
Top