Distribution of radial velocities in a gas

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The discussion centers on the distribution of radial velocities in a gas where particles have a uniform direction distribution but a constant absolute velocity. Observing from a distance, only the radial velocities within the range of [-v, v] can be detected. The key question raised is about the shape of the velocity distribution curve and whether it would be uniform, as suggested by the lecturer. It is noted that the velocity vectors form a sphere, and the observed distribution can be derived by calculating the surface area as a function of the chosen coordinate. Understanding this distribution is crucial for accurately interpreting the observed velocities of gas particles.
Arnoldas
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The lecturer did not explain this for some reason.

Assuming that we have a gass where all the particles have a certain absolute velocity v. Directions of v vector are random though, giving velocity vector a uniform direction distribution. That means that a velocity vector of any random particle has equal probability to point in any direction. But what if we observe this gas from a very far distance ( like atmosphere of a star): we can then only observe the radial velocities of particles. That means that we would observe all velocities in the interval [-v,v]. But the question is what would be the distribution that we would observe (particles per velocity curve)? for example which velocity would be most prominent? Would it also be a uniform curve?-thats what lecturer claimed in haste.
 
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All have the same velocity v? Then their velocity vectors form a sphere, and "seen from far away" you can pick one coordinate as your "observed direction". Then you just have to find the surface area as function of this coordinate, which is a formula you can look up (or derive yourself).
 
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