# Dive Bomber Questions

1. May 16, 2007

### MJC8719

A bomber is flying horizontally over level terrain, with a speed of 265 m/s relative to the ground, at an altitude of 3200 m. Neglect the effects of air resistance.

(a) How far will a bomb travel horizontally between its release from the plane and its impact on the ground?

(b) At what angle from the vertical (less than 90°) should the telescopic bombsight be set so that the bomb will hit the target seen in the sight at the time of release?

Hey,

So this problem has been giving me a little trouble.

I believe I have solved for part A correctly:
vy^2 = -2g(change in y)
vy^2 = -2(-9.8)(3200)
vy = 250.4396

vy = -gt
250.4396 = 9.8t
t = 25.5551

horizontal distance = 25.5551 x 265 = 6772.10 m

I am really having trouble understanding what part B is asking for. If someone could put me in the right direction, I would really appreciate it.

Thanks

2. May 16, 2007

### NateTG

What is the effective angle that the bomb falls at?

3. May 16, 2007

### MJC8719

Ok so this may seem like a stupid question, but what exactly does that mean? I cannot think of a formula to relate to this...i am guessing i want to set up something up that will allow me to determine the angle at which the bomb is dropped that allows it to have enough time to hit the target accurately. Basically, I need to determine the at what angle the bomb will hit its target given a time

So in this case, It takes the bomb 25.56 seconds to fall and it covers a horizontal distance of 6772.10 meters and hits the ground. I cannot figure out how to determine whether or not the bomb will have accurately hit the target....if someone could give me a little nudge in the right direction that would be great

4. May 16, 2007

Does the question involve a picture? I just want to know if you are looking for the angle between the line of sight and the vertical or between the line of sight and the horizonatal...I would assume it is the former (vertical).

5. May 16, 2007