Does a charge radiate only when changing direction?

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An accelerating charge, such as an electron, radiates energy, and this radiation occurs regardless of whether the acceleration is linear or involves a change in direction. In the context of an electron in a stable orbital, like in hydrogen's ground state, classical electromagnetism does not apply, and quantum mechanics is necessary to understand its behavior. The discussion highlights the confusion between energy and power, emphasizing that the Larmor formula calculates radiated power rather than total energy loss. The question of how much energy is needed to compensate for bremsstrahlung radiation remains, particularly for an electron with a kinetic energy of 13.6 eV. Ultimately, the complexities of classical and quantum mechanics must be navigated to fully grasp these phenomena.
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They say that an electron accelerating radiates and loses energy, and that is one of the reasons why an electron cannot orbit a nucleus:

- 1) does a charge accelerating in a straight line radiate, and what is the rate of radiation? do we have to supply extra Ke (apart from m/2 v^2) when we accelerate an electron?

- 2) Ke in the ground state of hydrogen is 13.6 eV, what energy per second should we supply anelectron to keep it in orbit,? I tried to apply the formula at wiki, but I get 1 Tera eV
 
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alba said:
- 2) Ke in the ground state of hydrogen is 13.6 eV, what energy per second should we supply anelectron to keep it in orbit,? I tried to apply the formula at wiki, but I get 1 Tera eV

None. The electron in the ground state is already in a stable orbital and cannot drop down any further. Note that classical E&M rules don't apply at the atomic level. For that you need Quantum Mechanics.
 
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I am referring to the classical model, of course. I'd like to know how much extra energy is necessary to compensate the bremsstrahlung.

My main question, anyway, concerns an accelerating charge in a straight line, does it radiate?
 
alba said:
I am referring to the classical model, of course. I'd like to know how much extra energy is necessary to compensate the bremsstrahlung.

My main question, anyway, concerns an accelerating charge in a straight line, does it radiate?
Why not?
Fast charged particles can be brought to a halt when they enter a solid mass and they release high energy radiation. That would involve 'linear' (negative) acceleration over a very short time (/ distance). I can't think of a mechanism that would produce positive acceleration with as high a value - except in nuclear reactions. But that would instantly take you into the realms of non-classical Physics.
But you seem to be requiring an 'unhealthy' mix of Classical and QM, which usually means tears before bed time. :smile:
 
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sophiecentaur said:
Why not?
But you seem to be requiring an 'unhealthy' mix of Classical and QM, which usually means tears before bed time. :smile:

No, I am simply asking what happens when you accelerate (not decelerate) an electron.
Also, I am asking, if a charge circles a nucleus with 13.6 eV Ke , how much energy is needed to compensate bremsstrahlung. According to Larmor formula it should exhaust its Ke in 10^-11 seconds., but I think it is naive to multiply 13.6 by 10^11. That's how I got 1 Tera eV. Did you get that?
 
alba said:
what happens when you accelerate (not decelerate) an electron.
There is no difference. It's the same thing in different frames.
 
It seems like you are confusing energy and power. Larmor formula gives a radiated power, not an energy.
 

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