Does Convergence of a Series Imply Convergence of Its Terms Over n?

[ehrenfest]

[SOLVED] convergence of a series

Homework Statement

Prove that the convergence of \sum a_n implies the convergence of \sum \frac{a_n}{n} if a_n \geq 0.

Homework Equations

The Attempt at a Solution

I want to use the comparison test. So, I want to find N_0 so that n \geq N_0 implies \frac{\sqrt{a_n}}{n} \leq a_n which is clearly not in general possible. So I am stuck. Maybe I need to replace a_n by a subsequence of a_n or something?

 

[ircdan]

consider any partial sum A_m = Sum(a_k/k, k = 1,..., m).

|A_m| = |a_1/1 + ... + a_k/k| = |(1/1) * a_1 + ... + (1/k)*a_k| <= ...

 

[ehrenfest]

Sorry. I am trying to prove
<br /> \sum \frac{\sqrt{a_n}}{n}<br />

converges not

<br /> \sum \frac{a_n}{n}<br />

For some reason, I cannot edit the opening post.

 

[ircdan]

ok even easier, just means you won't have to show something else I had in mine,

Let A_m = sum(sqrt(a_k)/k, k = 1,..., m) be any partial sum, then

|A_m| = |sqrt(a_1)/1 + ... + sqrt(a_k)/k| = |(1/1)*sqrt(a_1) + ... + (1/k)sqrt(a_k)| <= ...

use some famous inequality for the next step(not the triangle inequality), what's the other one I'm sure you know!

 

[ehrenfest]

Cauchy-Schwarz. Yay!

BTW you're k's and m's are mixed up.

 

[ircdan]

Cauchy-Schwarz. Yay!

BTW you're k's and m's are mixed up.

woops yea, good to see you got it! I'll look at your other question now