Does Friction Affect the Acceleration of a Sliding Block?

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AI Thread Summary
The discussion focuses on calculating the forces acting on a block with given coefficients of static and kinetic friction. To start the block sliding, a minimum horizontal force of 23.3 N is required, derived from the static friction equation. Once the block is in motion, applying the same force will not result in constant velocity due to the opposing kinetic friction, leading to acceleration instead. The net force can be determined using Newton's second law, which clarifies the relationship between applied force and friction. The participants successfully navigate through the calculations and confirm their understanding of the concepts involved.
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Homework Statement


The coefficient of static friction between a block and a horizontal floor is 0.44, while the coefficient of kinetic friction is 0.10. The mass of the block is 5.4 kg and it is initially at rest.

(a) What is the minimum horizontal applied force required to make the block start to slide?
(b) Once the block is sliding, if you keep pushing on it with the same minimum starting force as in part (a), does the block move with constant velocity or does it accelerate?
(c) If it moves with constant velocity, what is its velocity (in m/s)? If it accelerates, what is its acceleration (in m/s2)?


Homework Equations


F = ma
fs = usN


The Attempt at a Solution



a) F=ma
F=(5.4kg)(9.8m/s/s) = 52.92, which isn't right

b) I believe it will accelerate.

c) It's not 9.8 m/s/s. I will probably have to find it via F=ma?

Thanks so much for your help!
 
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Well, I figured out part a! a = 5.4 kg * 9.8m/s/s *.44 = 23.3. Still unsure about the rest though.
 
inkandgold said:
Well, I figured out part a! a = 5.4 kg * 9.8m/s/s *.44 = 23.3. Still unsure about the rest though.
You can answer the rest by using Newton's 2nd Law, Fnet = ma, where Fnet is the algebraic sum of the applied force and the friction force. Watch plus/minus signs.
 
Thanks so much, got it now!
 
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