Does Parity Operator Squared Equal Identity Operator?

UrbanXrisis
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just wondering... does the parity operator squared give the identity operator?
 
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What, exactly, is the definition of the "parity operator"?
 
what would happen if you take a wave function Psi and apply the Parity operator twice?
try it
 
hehe... so it WOULD be an like the identity operator
 
Oh. I thought this was a MATH problem!
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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