Does peltier effect account for lose of voltage of the cell?

AI Thread Summary
The Peltier effect, which creates a temperature difference from an electric voltage, can contribute to the loss of voltage in a battery due to the opposing Seebeck voltage. While the Seebeck effect is understood, the mechanics of the Peltier effect, particularly the release of heat during electron flow, raises questions. Once a battery is connected, the Peltier effect is activated, and the current flow generates heat at the junction, but the Seebeck effect does not occur until the battery voltage drops below the junction's output. The discussion clarifies that the Seebeck effect cannot contribute to battery voltage loss while the battery is connected and charged. Overall, the relationship between these thermoelectric effects is complex and requires careful consideration.
Ahmed Abdullah
Messages
203
Reaction score
3
The Peltier effect is the reverse of the Seebeck effect; a creation of a heat difference (between two joint) from an electric voltage.

This temperature difference gives rise to a seebeck voltage which is opposite to the voltage of the cell. So we can resonably conclude that it can contribute to the loss of voltage of the battery, can't we?

I understand seebeck effect but not peltier ... I don't understand why heat energy should be released when electron flow from a higher density to lower density site when it is propelled by an energy source (battery).
 
Physics news on Phys.org
Well yea...but...

Ahmed Abdullah said:
The Peltier effect is the reverse of the Seebeck effect; a creation of a heat difference (between two joint) from an electric voltage.

This temperature difference gives rise to a seebeck voltage which is opposite to the voltage of the cell. So we can resonably conclude that it can contribute to the loss of voltage of the battery, can't we?

I understand seebeck effect but not peltier ... I don't understand why heat energy should be released when electron flow from a higher density to lower density site when it is propelled by an energy source (battery).


Why would that ever happen in real life? Once you connect a battery, you get the peltier effect. Adding heat at this point won't change anything. You are trying to out think the process and you really shouldn't.
 
Video Eddie said:
Why would that ever happen in real life? Once you connect a battery, you get the peltier effect. Adding heat at this point won't change anything. You are trying to out think the process and you really shouldn't.

Would you explain things, a bit?
 
Ahmed Abdullah said:
Would you explain things, a bit?

When you apply a voltage, you have the peltier effect. The battery discharges at a rate dependant upon the resistance if the junction times the current flow. While the current flow does carry heat to one side of the junction. There is no Seebeck effect until the battery voltage drops below what the heated junction produces. After the heated junction output voltage is greater than the battery voltage, the Seebeck effect could recharge the battery to the point where the battery voltage equaled heated junction output voltage, but really the voltage would be very small by then.

The Seebeck voltage really can't contribute to the loss of battery voltage since it does not occur when the battery is connected and charged.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top