Does Pressure Affect Tyre Mass?

  • Thread starter Thread starter captainjack2000
  • Start date Start date
  • Tags Tags
    Pressure
AI Thread Summary
A fully inflated tire has a slightly greater mass than a punctured or uninflated tire due to the air inside it. The added mass comes from the air, which contributes to the overall weight but is minimal compared to the tire's mass. While the pressure in a fully inflated tire is higher, the difference in mass is not significant. Therefore, the mass difference is primarily due to the air, which has a low density. Overall, the increase in mass from inflation is negligible.
captainjack2000
Messages
96
Reaction score
0

Homework Statement


Just a quick question: does a fully inflated tyre have the same mass as a tyre that is punctured or uninflated?


Homework Equations





The Attempt at a Solution


The one that is fully inflated will have a greater pressure but I am not sure what this will mean in terms of the mass...
 
Physics news on Phys.org
No, but not much more. The pressure is, of course, because of air in the tire. The fully inflated tire has more air inside it and so has the mass of that air added to the mass of the tire itself. Since air does not have a great deal of mass compared to the tire, the increase in mass is not very much.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

An inflated tyre suddenly bursts -- What is the temperature of the air?
Replies
9
Views
4K
High Pressure in Tyres, Won't Burst
Replies
1
Views
2K
Pressure on tyres of a vehicle question - Calculating weight
Replies
6
Views
3K
Fluid Mechanics: Pressure Question
Replies
4
Views
2K
Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
Replies
13
Views
2K
Total area of contact between tires and ground?
Replies
15
Views
9K
Clarifying the Definition Total/Stagnation Pressure (p₀) in Bernoulli'
Replies
2
Views
892
Calculate the ratio of new volume to old volume
Replies
2
Views
3K
Reaction time while stopping a car
Replies
29
Views
3K
What is the temperature and mass of air in a tire after a change in pressure?
Replies
9
Views
3K

Hot Threads

Recent Insights

Back
Top