Does the electric field reach a value equal to half its maximum value?

AI Thread Summary
The discussion centers on determining the distance from the center of a non-conducting sphere where the electric field equals half its maximum value. A user initially calculated the electric field incorrectly by simply dividing charge by radius, which does not yield the correct electric field units. It was suggested to apply Gauss' Law to accurately derive the electric field as a function of radius and identify where the maximum occurs. Additionally, it was noted that there are actually two radii at which the electric field reaches half its maximum value. The conversation emphasizes the importance of using proper formulas in electrostatics.
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A non-conducting sphere of radius R = 7 cm carries a charge Q = 4 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere does the electric field reach a value equal to half its maximum value?

My attempt:

Emax= q(4mC)/7
r= 7/2 cm = 3.5

is this correct? because one of my friend said 9.9... so idk if I am right or are both values
 
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I'm not sure how exactly you determined the maximum of the electric field. It appears that all you did was divide the charge by the radius. This is not a correct formula and doesn't even give you the units of an electric field. My suggestion would be to use Gauss' Law to find the electric field as a function of radius. This will allow you to determine at what radius the maximum occurs (although with a bit of experience it should be fairly obvious). From there you can set the equation for the field equal to half that value and solve for r.

Just a hint, there should actually be two radii at which the field is equal to half its maximum.
 
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I agree with your friend.
 
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