Does the moon orbit as a classical particle?

AI Thread Summary
The moon orbits Earth at a distance of approximately 3.84E8 m, and to determine if it behaves as a classical particle, its matter wavelength must be compared to this orbit radius. Using De Broglie's equation, the wavelength can be calculated as λ = h/(mv), where v is derived from gravitational dynamics. The key is to assess whether the calculated wavelength is of the same order of magnitude as the orbit radius. If the wavelength is significantly smaller than the orbit radius, it supports the notion of the moon behaving as a classical particle. Ultimately, this comparison will clarify the moon's orbital behavior in classical mechanics.
Big_Tubbz
Thread moved from a technical forum, so homework template missing
The moon orbits Earth at a radius of 3.84E8 m. To do so as a classical particle, its wavelength should be small. But small relative to what? Being a rough measure of the region where it is confined, the orbit radius is certainly a relevant dimension against which to compare the wavelength. Compare the two. Does the Moon indeed orbit as a classical particle? (MEarth=5.98E24 kg and MMoon=7.35E22 kg)

I know I need to use De Broglies equation but I don't know what it means by "compare the two". How do I compare the moon's matter wavelength to its orbit? And how do I, from this determine whether it orbits as a classical particle?

Relevant equations: λ=h/(mv), F=mv^2/r, F=GMm/r^2

Do I solve for V and then use that in the wavelength equation? How does that tell me how small it is in relation to the orbit.

v=sqrt(GM/r) λ=h/(m*sqrt(GM/r))
 
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You have two values, the orbit radius and the wavelength, which have the same units. Are they the same order of magnitude? Do they differ by a small factor (2? π?). Or is one incredibly small compared to the other?
 
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