Does the Vector Space Axiom Hold for V with Given Conditions?

Rigid@motion
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let V be the collection of the 2*3 matrices with a real entries such that
V={[a11 a12 a13 : a21 a22 a23] | a11+a23 =1}
determine whether the following vector space axioms holds
(a) for all α ε V there exists (-α) such that α + (-α)=0(vector)
 
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Rigid@motion said:
let V be the collection of the 2*3 matrices with a real entries such that
V={[a11 a12 a13 : a21 a22 a23] | a11+a23 =1}
determine whether the following vector space axioms holds
(a) for all α ε V there exists (-α) such that α + (-α)=0(vector)
please help
 
Wow! You waited a whole 12 minutes before "bumping"! I would think that when you read through the information that you had to say you had read when you registered here, you would have seen that bumping, even after days, is prohibited and can get you barred.

Also in those same documents you said you read, you are told that anything that looks like school work or homework- which this certainly is- you must make an attempt to do the problem yourself and show your work.

I will move this the homework section and give you 24 hours to post what you have tried on this yourself. If you have not put anything up by that time, I will delete this thread.

(If you know the definitions of "0 vector" and "additive inverse" ("negative") of a vector, this problem should be easy. If you don't know those definitions, the first thing you should have done was look them up.)
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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