Does This Recursively Defined Sequence Converge?

workerant
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[SOLVED] Convergence of a Sequence

Homework Statement


Consider the following "recursively defined" sequence:

a1=0.3
a(n+1)=sqrt (an+1)

Compute the first first five terms and prove that it converges. Then, find the limit of the sequence.


Please see:

Problem 3, particularly parts c and d here for the complete problem:

http://rutcor.rutgers.edu/~ngoldberg/math152/ws0837.pdf



The Attempt at a Solution



I would try to show that the sequence is increasing and bounded because that shows that it converges. I am not sure, however, how to go about doing this.

I think I am okay with finding the first five terms. I suppose the second term would be a2= sqrt (a1+1)=sqrt (1.3) and so on and so forth and it would get quite complicated.

I am not sure how to go about the proof and finding the limit.


Thank you.
 
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Welcome to PF!

workerant said:
I would try to show that the sequence is increasing and bounded because that shows that it converges. I am not sure, however, how to go about doing this.

Hi workerant! Welcome to PF! :smile:

Do one step at a time!

First step is to prove that a_n+1 > a_n.

In other words, that √(1 + a_n) > a_n

Hint: what is the condition for √(1 + a) > a? :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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