Does work increase if q increases?

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Increasing the magnitude of a positive test charge does not change the electric field, so the work done remains the same, as expressed by the equation W = E*q*d*cos(theta). The force on the test charge is affected by the electric field, calculated using F = Eq. The electric field diverges from positive charges and converges towards negative charges, resulting in repulsive interactions with positive charges and attractive interactions with negative charges. The direction of the force changes if the test charge is negative, but the magnitude remains constant. Overall, the work done on the test charge remains unchanged regardless of its magnitude.
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Homework Statement


If positive work is done on a positive test charge will the work increase,decrease or stay the same if the test charge increase


Homework Equations


W=fa W=∆K

The Attempt at a Solution


the magnitude of the test charge doesn't affect the Electric Field so the work will be the same
 
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W = E*q*d*cos theta. I'm not actually sure I understand the question to be honest
 
The magnitude of the field does affect the force on the test charge.
F=Eq
The Field is points (diverges/source) from positive charges to negative charges (converges/sink).
The field is repulsive with the positive charge. Attractive with the negative.
The magnitude will be the same, the direction different for a negative charge assuming the magnitude of the charge is the same.
Hope this helps.
Matt
 
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