Domain of a composite function

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To find the domain of the composite function h(g(x)), it is essential to determine the domains of both g(x) and h(x). The function g(x) is a polynomial, which has no restrictions on its domain, while h(x) requires that its input be greater than or equal to zero. Specifically, for h(g(x)) to be valid, g(x) must yield values that satisfy the condition g(x) ≥ 5. Solving the inequality 3 - 2x^2 ≥ 5 will provide the necessary values of x for which the composite function is defined. Understanding these relationships clarifies the process of finding the domain of composite functions.
ilii
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Homework Statement


Given the Functions
f(x)=4x-1
g(x)=3-2x^2
h(x)= sqrt (x+5)

What is the domain of h(g(x))?

Homework Equations



the subject is finding the domain of a composite function

The Attempt at a Solution


I don't understand what I have to 'bring over' from g(x). I think x cannot equal zero for g(x). If someone could post a structured list of steps I need to take to find the domain of a composite function, it would be much appreciated.

thank you
 
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The domain of a composite function (f \circ g)(x)=f(g(x)) is defined as D(f\circ g)=\{x \epsilon D(g) | g(x) \epsilon D(f) \}. So you should find the domains of f and g and check that for what subset of the domain of g, it gives values in the domain of f.
 
ilii said:

Homework Statement


Given the Functions
f(x)=4x-1
g(x)=3-2x^2
h(x)= sqrt (x+5)

What is the domain of h(g(x))?

Homework Equations



the subject is finding the domain of a composite function

The Attempt at a Solution


I don't understand what I have to 'bring over' from g(x). I think x cannot equal zero for g(x).

thank you

Why do you think that? ##g(x)## is just a polynomial. What' wrong with ##g(0)##?
What is the formula for ##h(g(x))##? What values of ##x## work in that?
 
The domain of square root is "numbers greater than or equal to 0". h(x)= sqrt(x- 5) so the domain of h is "x- 5\ge 0 or x\ge 5. That means that g(x)= 3- 2x^2 must give only values greater than or equal to 5. Can you solve 3- 2x^2\ge 5?
 
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thanks everyone I understand it much better now :D
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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