Domino Experiment: Time Dependence on Number of Dominoes

  • Thread starter Thread starter cerebro
  • Start date Start date
  • Tags Tags
    Experiment
AI Thread Summary
The discussion centers on an experiment measuring the time it takes for a row of dominoes to fall after the first one is pushed. The relationship between the number of dominoes and the time taken for them to be knocked down is questioned, particularly considering factors like rotational inertia. It is suggested that optimal spacing between dominoes could influence the speed of wave propagation, with trade-offs between linear impulse and angular momentum. The impact of domino shape, size, and weight on this relationship is also noted. The conversation highlights the complexity of the physics involved and the potential for finding an optimal configuration through further exploration.
cerebro
Messages
1
Reaction score
0
I made such experiment: I calculated the time dependence on the number of dominoes. The dominoes are set up in a row with a constant distance between them.

However the measurements are not necessarily exact and that is why I have a question:

What should be the relation between the number of dominoes set up in a row and the time that takes them to be demolished after I push the first one.
 
Physics news on Phys.org
hmmm...i got a feeling that rotational inertia also needs to be taken into account, since the domino is rotating(sort of).
 
A similar question has stymied me for quite some time; that being, for a given domino shape/size/weight, is there an optimal spacing that will produce the fastest wave propagation?
 
I would think it's a little predictable to some extent, since the only forces on a domino are its inital impulse plus gravity. When dominos are spaced farther apart, they hit the next domino with a greater linear impulse but transmit a smaller angular momentum (because it hits the domino at a point closer to the center of mass -- less r). On the other hand, closer dominos transmit more angular momentum per linear impulse, but the impulse is less because it has had less time to accelerate. Interesting question, and I bet there is a "best-case" solution for a standard size/weight domino that would take a few iterations to solve. When I have a little time to think about it more I'll respond again...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top