Doppler effect when moving towards then past each other

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SUMMARY

The discussion centers on calculating the speed of an emergency vehicle using the Doppler effect. When the vehicle approaches, the observed frequency of the siren is 2800 Hz, and when it passes, the frequency drops to 2120 Hz. The speed of sound in air is given as 340.0 m/s, and the observer's speed is 27.50 m/s. The formula used is F2 = F1(vsound/(vsound ± vobject), where the sign depends on whether the object is approaching or receding.

PREREQUISITES
  • Understanding of the Doppler effect
  • Familiarity with frequency and wave concepts
  • Basic algebra for solving equations
  • Knowledge of sound speed in air (340.0 m/s)
NEXT STEPS
  • Calculate the speed of the emergency vehicle using the provided Doppler effect formula
  • Explore variations of the Doppler effect in different mediums (e.g., water, solids)
  • Study real-world applications of the Doppler effect in radar and astronomy
  • Learn about sound wave properties and their impact on frequency perception
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Physics students, educators, and anyone interested in understanding sound wave behavior and the Doppler effect in real-world scenarios.

PHolloway27
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You are driving along a highway at 27.50 m/s when you hear the siren of an emergency vehicle traveling in the opposite direction on the other side of the highway. When the vehicle is approaching you, you hear the frequency of the siren as 2800 Hz, but when it is past you the frequency becomes 2120 Hz. What is the speed of the emergency vehicle? The speed of sound in air is 340.0 m/s.
 
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Hi PHolloway27! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Seems like classic doppler to me

F2=F1(vsound/(vsound+/-vobject)

+ recceding
- approaching

just plug in the right numbers
 

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