Double Differentiation and Acceleration in a Four Pulley System

AI Thread Summary
The discussion centers on calculating the acceleration of block B in a four-pulley system, with an established acceleration of a_B = 0.5 m/s². Participants debate the relationship between the movements of blocks A and B, clarifying that if block A moves up by 1 meter, block B also moves up by 1 meter due to the connection of the pulleys with inextensible ropes. The conversation emphasizes the need for careful consideration of the pulley mechanics, suggesting that while some blocks remain stationary, others will move in response to A's movement. Visual aids or experiments are recommended to better understand the system dynamics. The discussion highlights the importance of accurately analyzing the motion of interconnected systems.
rudransh verma
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Homework Statement
The vertical displacement of block A in meters is ##y=\frac{t^2}4## where t is in sec. Calculate the downward acceleration of block B.
Relevant Equations
##F=ma##
We can differentiate twice the y displacement with respect to time t and get the acceleration of block B. $$a_B= \frac12 m/s^2$$.
But I don’t think it’s that simple.
 

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You think correctly :smile:
But at least you have the acceleration of A.
How is the position of B in relation to A ? (if A moves up 1 m, how much does B move?)

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BvU said:
You think correctly :smile:
:smile:
BvU said:
How is the position of B in relation to A ? (if A moves up 1 m, how much does B move?)
Of course 1 m since all are connected with unstrechable ropes.
 
Your logic is faulty. Think again. Number the pulleys 1,2,3,4 left to right. If 1 goes up by 1 unit, 2 stays in position unchanged, 3 ... etc.

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BvU said:
Your logic is faulty. Think again. Number the pulleys 1,2,3,4 left to right. If 1 goes up by 1 unit, 2 stays in position unchanged, 3 ... etc.

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Oh like that!
1 goes up by 1 unit then 2 stays in place, 3 and 4 goes down by 1 unit.
 
2 correct
3 think again, perhaps do the experiment..., or make 2 drawings...

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