Double Integral of e^(x^4) HELP

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Homework Help Overview

The discussion revolves around evaluating a double integral of the function e^(x^4) with specified bounds involving variables y and x. Participants are attempting to clarify the correct limits of integration and the order of integration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the bounds, with one suggesting a correction to the lower bound from 3*(sqrt(y)) to the cube root of y. Questions arise about how to reset the limits of integration to facilitate integration with respect to y first.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing insights on how to sketch the region of integration and determine new limits. Guidance has been offered regarding the interpretation of bounds and the order of integration, but no consensus has been reached on a complete solution.

Contextual Notes

Participants are working under the constraints of the original problem statement and are questioning the assumptions made about the bounds of integration. There is an acknowledgment of potential confusion regarding the limits and the function to be integrated.

sarahlynnuoit
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Homework Statement



Integrate Double Integral of e^(x^4), First Bound- a = 3*(sqroot(y)) and b= 2 and 2nd Bound - C = 0 and D = 8?

Homework Equations





The Attempt at a Solution


We have been working on this all day and we have tried changing bounds but we cannot find an solution that can be integrated and we cannot get rid of the e^(x^4)
Please help! :)
 
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Do you by any chance mean:

[tex]\int_{0}^{8}\int_{\sqrt[3]{y}}^{2} e^{x^{4}} \ dx\ dy[/tex]

If so, then know that the lower bound is cube root of y, not 3 square root of y. That may be why you're not getting something that you can integrate when you reorder the variables. If you integrate first with respect to y, and then x, you will get something you can integrate.
 
So given that same problem how do you reset the limits of integration so you can integrate with respect to y first?
 
Sketch the region of integration [itex]2 \leq x \leq y^{1/3}[/itex] and [itex]0 \leq y \leq 8[/itex]. Now draw an arrow through your sketched region pointed in the same direction of the y-axis. The boundary the region that your arrow intersects first will be your new lower limit. The boundary of the region that your arrow intersects second will be your new upper limit.
 
y goes from 0 to 2, obviously. Now, for each y what bounds does x have?

That's basically what Samuelb88 is saying.
 
I see thanks for the info guys.
 

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