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∫∫_{R}5x^{2}+ 2y^{2}

where R is triangle (1,1) (2,0) (2,2)

I see the lines bounding the triangle are y=x y=2-x and x=2, and have tried many attempts at setting up the correct limits.

Would it be correct to split this into 2 triangles, or are the limits^{y=x}∫_{y=2-x}for y and^{2}∫_{1}for x, correct

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# Double Integral volumes: Triangular base

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