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Double Slit Intensity Problem

  1. Nov 22, 2014 #1
    1. The problem statement, all variables and given/known data
    Coherent light with wavelength 585 nm passes through two very narrow slits that are
    0.320 mm apart. The screen is 0.700 m away from the slits. The intensity is I0 at the
    centre of the central maximum (theta=0)

    (a) What is the phase difference (in radians) in the light from the two slits at an angle
    of 23degrees from the centre line?

    (b) What is the distance on the screen from the centre of the central maximum to the
    point where the intensity has dropped to I0/2?

    2. Relevant equations
    Φ=2π/λ*dθ
    I=I_0*cos2Φ/2


    3. The attempt at a solution
    a)
    (2pi*3.2x10^-4)/(5.85x10^-7)*23pi/180=439pi radians

    b) I=I_0cos^2(Φ/2)

    cos^2((pi/2)/2)=1/2

    So i figured Φ=2pi but the equation i wanted to use to solve is

    Φ=(2*pi*d)/(λ)*θ

    but i don't have a theta. For part a it was 23 but i figured there will be a completely new angle for this part of the question.

    Thanks
     
  2. jcsd
  3. Nov 22, 2014 #2

    mfb

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    2016 Award

    Staff: Mentor

    Well, you have to calculate it with that formula.
    You can get Φ with first equation you have in (b). It is not 2 pi (plug it in and see if the result would be right).
     
  4. Nov 22, 2014 #3
    i meant to put pi sorry.

    d is slit separation right? i think i was getting mixed up and thinking it was distance from screen to centre
     
  5. Nov 22, 2014 #4

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Looks like slit separation in your formula.

    Pi is still wrong. Please stop guessing and calculate the value.
     
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