Double slit interference pattern

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Homework Help Overview

The problem involves a double slit interference pattern created by light of wavelength 500 nm passing through slits separated by 0.320 mm. The original poster seeks to determine the number of maxima within the angular range of -30 degrees to 30 degrees.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the number of maxima using the formula d*sin(theta) = m*(lambda), leading to a conclusion of 640 maxima. Some participants question the validity of this conclusion by suggesting alternative angular ranges, prompting a discussion on the implications of different limits on the number of observable maxima.

Discussion Status

Participants are exploring the implications of the specified angular range and questioning whether the original poster's interpretation aligns with the problem statement. There is no explicit consensus, but some guidance is offered regarding the consideration of different ranges for maxima.

Contextual Notes

There is an ongoing discussion about the constraints of the problem, particularly regarding the specified angular limits and their impact on the number of maxima calculated. Some participants express uncertainty about the interpretation of the problem statement.

svitak
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Homework Statement



Two slits are separated by 0.320 mm. A beam of 500-nm light strikes the slits, producing an interference pattern. Determine the number of maxima observed in the angular range -30 degrees < theta < 30 degrees.

Homework Equations



d*sin(theta) = m*(lambda)


The Attempt at a Solution



(.32)sin(30)/.0005mm = m
m=320

so there are 320 maxima in 30 degrees. and thus 640 in this total range. is that right?
 
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Seems fine to me.
 
There is a problem.
What if it's from -0.001 degrees to 0.001 degrees? Find m corresponding to that case and you will find out what you missed :wink:
 
hikaru1221 said:
There is a problem.
What if it's from -0.001 degrees to 0.001 degrees? Find m corresponding to that case and you will find out what you missed :wink:

I think your comment has weight...but the range of visibility of this diffraction pattern are already set in place...namely between 30 and -30 degrees. OP, correct me if I'm mistaken in my interpretation of your problem statement, please.
 
I'm not entirely sure what you are getting at. But, I'm pretty sure it is meant to be strictly limited to 30 and -30.
 
No, I mean, what if the question asks for the number of maxima in another range. Just replace -30 with -0.001 and 30 with 0.001, solve the problem again, and you will see why.
 

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