We have the wavelength of 550nm and the distance (d) of 0.120mm. I need to calculate the the angle q.
The diffirent parts of this questions corresponds to the diffirent order of n. a) Being n=1 b) n=5 c) n=10
Wavelength = 550nm = 550*10^-9m
d=0.120mm = 0.00012m
n2 = 10
The relevant equation for this is;
d*sin0 = n*Wavelength
0 = sin((n*Wavelength)/d))
The Attempt at a Solution
I've attempted the solution to this and my real problem is that I have got no idea how to get the answer to Degrees. I'd really like to see someone do this so I can see what you do and how I should think.