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Evaluate sin(tan^{-1}(\frac{1}{3}))
3. The Attempt at a Solution
Let y = tan^{-1}(\frac{1}{3})
<=> tan(y)=1/3
y = ?
sin(tan^{-1}(\frac{1}{3})) = sin y
I think for solution to exist tan^{-1}(\frac{1}{3}) must be in the range of sin, (that is \left\frac{-\pi}{2}, \frac{\pi}{2}[\right]
i'm not sure how to evaluate this. :(
3. The Attempt at a Solution
Let y = tan^{-1}(\frac{1}{3})
<=> tan(y)=1/3
y = ?
sin(tan^{-1}(\frac{1}{3})) = sin y
I think for solution to exist tan^{-1}(\frac{1}{3}) must be in the range of sin, (that is \left\frac{-\pi}{2}, \frac{\pi}{2}[\right]
i'm not sure how to evaluate this. :(