Drawing a FBD for a Cup Spinning on a Lazy Susan

  • Thread starter Thread starter crybllrd
  • Start date Start date
  • Tags Tags
    Fbd Perspective
AI Thread Summary
When drawing a free body diagram (FBD) for a cup spinning on a Lazy Susan, the perspective can be chosen based on clarity. The downward force of gravity should be represented in the diagram regardless of whether the view is from the side or top. The friction force acts toward the center of the turntable and remains consistent in both perspectives. It's important to represent forces accurately, using an X in a circle for forces directed into the page. Ultimately, the choice of perspective should enhance the understanding of the forces acting on the cup.
crybllrd
Messages
120
Reaction score
0

Homework Statement


A cup is spinning around on a Lazy Susan...

Homework Equations


The Attempt at a Solution


My question is about the perspective. The picture on my book is like this:
___________|---0.5m---\_/
=====================


So should I draw the free body diagram from this perspective, with the weight by the Earth on the cup pointing down, or from the top down perspective where I can see the friction force?
 
Physics news on Phys.org
You can go either way. Show forces into the page as an X in a circle.
The friction force would be toward the center of the turntable, so would look the same in either view.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Potential Mistake in Free-Body Diagram
Replies
5
Views
2K
Finding minimum force to pull the napkin out from under the tea cup
Replies
7
Views
2K
What will the FBD of 2 blocks being pulled look like?
Replies
7
Views
2K
FBD of an aerogenerator (Windmill)
Replies
3
Views
1K
Draw the F.B.D. (Free Body diagram) of two blocks
Replies
6
Views
3K
Forces on a Window: 3 Suction Cups & Normal Force
Replies
7
Views
1K
Free Body Diagram of Mass-Spring System
Replies
5
Views
1K
Center of mass and momentum- A question about systems
Replies
25
Views
1K
Which forces am I missing in the FBDs?
Replies
9
Views
2K
Friction - problem with one of the equilibrium equations
Replies
13
Views
1K

Hot Threads

Recent Insights

Back
Top