Drawing lemonade of density 1000 kg/m3 up a straw to a maximum height

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To determine the minimum gauge pressure required to suck lemonade with a density of 1000 kg/m3 up a straw to a height of 3.3 cm, the formula P = pgh is applied, resulting in a pressure of 323.73 Pa. This value is then converted to atmospheres by dividing by 1.0125e5, yielding approximately 3.197e-3 atm. The discussion highlights confusion regarding the negative sign in gauge pressure calculations, which can occur when considering atmospheric pressure as a reference point. The participants clarify that negative gauge pressure is valid and can indicate a pressure below atmospheric levels. Understanding these conversions and the concept of gauge pressure is essential for solving similar problems.
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To suck lemonade of density 1000 kg/m3 up a straw to a maximum height of 3.3 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?

I know i need to use P=pgh which equals 1000(9.81)(.033)
which equals 323.73
-Then i divide, so, 323.73/1.0125e5
that equals 3.197e-3

It said that my answer was wrong. It looks good to me. Thanks for the help.
 
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What's the conversion you are using from mks units to atmospheres?
 
You're answer better be negative.
 
thanks man, it was negative.
 


I just did this problem and was wondering why the answer was negative? How often can pressure be considered negative?

Thanks for the help!

~Phoenix
 
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