Drop a stone in a well - Waves problem

[ghostanime2001]

Homework Statement

You drop a stone from rest into a well that is 7.35 m deep. How long does it take before you
hear the splash?

d=7.35 m
v=343 m/s (because the disturbance is air molecules and the medium is air not water)

Homework Equations

d=\dfrac{1}{2}gt_{1}^{2}

\lambda=4d and v=\lambda f and we know that f is f=\dfrac{1}{T}

The Attempt at a Solution

The time taken for the stone to drop in water:
t_{1}=\sqrt{\dfrac{2d}{g}}=1.22 s

The time taken for the reflected wave to make it outside the well
v=\dfrac{4d}{T}
So, T=\dfrac{4d}{v}=\dfrac{4(7.35)}{343}=0.0857 s

Finally,
t_{total}=t_{1}+t_{2} = 1.22 s + 0.0857 s = 1.3 s

However this is wrong! the answer is 1.24 seconds. What am i doing wrong?

My first initial thought is to think of the well as an open-closed tube. When those relevant equations are applied to a open-closed tube I get the wrong answer. Why is thinking of the well as a open-closed tube wrong ?

1. Is it because a little portion of the well at the bottom is filled with water so that the ENTIRE well is not actually 7.35 m ? OR

2. Is it because we have no information about its wavelength regardless if it's a open-closed tube? OR

3. Does the wavelength calculated above does not make sense ? (e.g. How can the wavelength be 29.4 m when the well itself is 7.35 m ? (Assuming the well as a long cylinder)

 

[technician]

You have the time for the stone to fall and hit the water correct = 1.22s
This makes a noise and the sound has to travel to the top of the well, 7.35m and the speed of sound = 343m/s. Calculate the time taken for sound to travel this distance.
How much time has passed since you dropped the stone??

 

[ghostanime2001]

But what about the wavelength of the sound wave? I can't change the wavelenght.