During a tornado, softer objects are driven through apparently harder objects

  • Thread starter Thread starter Dmitri10
  • Start date Start date
  • Tags Tags
    Tornado
AI Thread Summary
Softer objects can penetrate harder objects during a tornado due to the dynamics of mass and inertia. The greater mass of harder objects makes them more resistant to movement, allowing softer objects to pass through instead of being deflected. This explanation, while plausible, raises questions about its applicability outside tornado conditions. The discussion highlights the need for a more thorough investigation into the specific mechanics at play during tornado events. Understanding these interactions is crucial for a comprehensive explanation of the phenomenon.
Dmitri10
Messages
19
Reaction score
0

Homework Statement


During a tornado, softer objects are driven through apparently harder objects. How is this possible?

Homework Equations


none

The Attempt at a Solution


The harder objects have greater mass, and thus more inertia, so they are more difficult to move. Rather than move when the softer objects hit them, the harder object stays put and the softer objects go through.

Is this correct?
 
Physics news on Phys.org
It's a hypothesis, and you have a (hand-waving) argument for it.

But you should be suspicious -- it doesn't involve tornadoes at all. If correct, it would imply that "softer objects driven through apparently harder objects" under non-tornado conditions as well.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top