Dynamics Homework Help, velocity, acceleration of particle

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The discussion centers on a dynamics homework problem involving the velocity and acceleration of a particle. The user seeks assistance in understanding how to approach the problem and requests clarification on their calculations. They mention that the tangential speed at a specific time is 180t, with a calculated velocity of 68.4 at 0.38 seconds. The tangential acceleration is noted as 180, while the normal acceleration is calculated to be 0.65. The resultant acceleration at the end of 0.38 seconds is approximately 180.
frank1234
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I need help with my dynamics homework. This is what I have so far, I hope you can read my writing (let me know if something is unclear). Can someone help me with how to approach this problem and where to go next? Thank you!
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Periphery of inner wheel and hence that of outer has tangential speed equal to 180t.now at t as found by you 0.38.
so v at the end of 0.38 sec equals 68.4(Pl. make corrections in your solution.)
Now tangential acc.=dv/dt=180
Normal acc.=-v^2/R3=-68.4/105=0.65
Resultant acc. at end of 0.38 sec=sqrrt(0.65^2+180^2)=180 approx.
 
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