E-field at various points from two large sheets

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Two large sheets of plastic are charged with surface densities of n1 = -n_o and n2 = 3n_o, creating a uniform electric field between them. The electric field strength is constant and independent of distance due to the large size of the sheets. To calculate the electric field at various points, the fields from each sheet must be added vectorially, taking into account their directions. The correct formula for the electric field produced by each plane is E_plane = n/2ε_o. Understanding the positioning of the points relative to the sheets is crucial for accurate calculations.
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E-field at various points from two "large" sheets

1.You've hung two very large sheets of plastic facing each other with distance d between them, as shown in the figure . By rubbing them with wool and silk, you've managed to give one sheet a uniform surface charge density n1 = -n_o and the other a uniform surface charge density n2 = 3n_o .



2. electric field equations



3. Ok, I know that since both sheets are "large" that their field strength is uniform and independent of distance. Thus, point 1, for example, I would just add the -n_0 and 3n_o since the field vectors for the left plate point to the right for point one and the vectors from the far plate point left... but how do I do this in terms of n_o / epsilon_o? I tried entering a numerical value based on the simple addition I described but its wrong.
 
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I've no idea what "point one" is, nor which plate is on the left and which is on the right. I think you're on the right track, however. Find the electric field produced by each plate and add them vectorially.
 


Sorry. Point 1 is the left of the left (-n_o) sheet, point to is in between the two sheets, and point 3 is to the right of the right sheet (3n_o).
 


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Nevermind, I got it. The readings this week were typed up wrong so I hadn't read the right sections. It was simple once I had the equation E_plane = n/2ep_o
 
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