- #1

Curtis15

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The E field outside of this sheet is sigma/2*epsilon naught

The E field outside of this conductor is sigma/epsilon naught, twice as strong as the infinite sheet.

I understand the derivations of this from Gauss's Law, but I am confused as to why a point outside each of these, at the same distance, would experience different forces. judging by the diagram, you would have each of the 15 plus charges creating an electric field to the right side, and in both surfaces, the charge distribution is equal, so why the difference?

In my mind, if you take away all the boxes, and just look at the plus signs, the charges seem to have the same arrangement in both boxes, so if you keep the distance that you place your charge outside the same, the force should be equal.

Any help is greatly appreciated, thank you.