What are the equations for trajectory in an E-field?

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The discussion focuses on the trajectory of an electron in a uniform electric field, particularly when it enters at an angle of 30 degrees above the field direction. Key concepts include the use of trigonometric functions, specifically tan, sin, and cos, to resolve the initial velocity into components. The equations provided for calculating the trajectory include v = ucos(ß) + at, v^2 = (ucos(ß))^2 + 2as, and s = (ucos(ß) x t) + 0.5at^2. Understanding these equations is crucial for solving related problems in the physics exam. Mastery of these concepts will aid in accurately predicting the electron's path in an electric field.
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Homework Statement



Hello, I have a physics exam on friday. My teacher said one of the questions would be on the TRAJECTORY (of an electron) IN AN E-FIELD. he told us to remember than tanß = sinß / cosß

we haven't used tan, sin or cos during class work. I was hoping someone could give me a clue to what he means.

Thanks
 
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he means that you will need to use tan(beta)
 
yes i know he will give us some form of equation or something to do with tanß
but how is this related to the trajectory in an e field?
 
say a uniform electric field points in the x direction. but the electron enters the E field at a certain speed 30 degrees above the direction of the E field, then you are going to have initial components of velocities that involve sine and cosine
 
So would the equations be:

v = ucosß + at
v^2 = (ucosß)^2 + 2as
s = (ucosß x t ) + .5at^2
?
 
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