1. The problem statement, all variables and given/known data Given: A 300 kg walkway supported by two rollers(at points A and B) with center of mass at G. Find: The tension T in the horizontal cable attached to the cleat at point B and the force under the roller at A. 2. Relevant equations ∑M = 0 ΣFx = 0 ΣFy = 0 3. The attempt at a solution Free body diagram of the bridge has Normal force vertically upwards with point of application A(Na) , Weight(W) vertically downwards at G, Normal force perpendicular to walkway directed away from water(Nb), and Tension(T) horizontal to the right at point B. ∑Mb = 0 (moment at point B) 0 = +W(4cos30°) - Na(8cos30°) Na = (W(4cos30°))/(8cos30°) Na = 1472 N So far this answer is known to be correct for Na. ΣFx = 0 0 = T - Nbcos30° T = Nbcos30° ΣFy = 0 0 = Na - W + Nbsin30° Nbsin30° = W - Na Nb = (W - Na) / sin30° Plugging in the known values and Na that we solved for yields the incorrect answer. Why can't I add up the components of the force vectors or what am I doing incorrectly?