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Easy difference quotient question

  1. Oct 8, 2008 #1
    1. The problem statement, all variables and given/known data
    Using difference quotient I am trying to find f '(0) for 2^x. Basically my question is a questions of algebra but I will show you what I have done thus far.

    the limit is as x -> 0

    [tex]\frac{2^x - 2^0}{x - 0}[/tex]

    [tex]\frac{2^x - 1}{x}[/tex]

    So my question is what can I do to get x off the bottom.
  2. jcsd
  3. Oct 8, 2008 #2


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    Homework Helper

    You've probably already proved that the limit x->0 of (e^x-1)/x=1. Try to use that.
  4. Oct 8, 2008 #3
    Thanks, that helped.
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