Easy difference quotient question

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SUMMARY

The discussion focuses on calculating the derivative of the function f(x) = 2^x at the point x = 0 using the difference quotient method. The limit expression presented is lim (x -> 0) (2^x - 1)/x. Participants confirm that leveraging the known limit lim (x -> 0) (e^x - 1)/x = 1 is a valid approach to simplify the calculation. The conclusion emphasizes that applying this limit will yield the derivative f '(0) = ln(2).

PREREQUISITES
  • Understanding of difference quotients in calculus
  • Familiarity with limits and their properties
  • Knowledge of exponential functions and their derivatives
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of the limit lim (x -> 0) (e^x - 1)/x = 1
  • Explore the properties of exponential functions, specifically f(x) = a^x
  • Learn about the natural logarithm and its relationship with exponential functions
  • Practice calculating derivatives using the difference quotient method for various functions
USEFUL FOR

Students studying calculus, particularly those learning about derivatives and limits, as well as educators seeking to clarify concepts related to exponential functions.

Sheneron
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Homework Statement


Using difference quotient I am trying to find f '(0) for 2^x. Basically my question is a questions of algebra but I will show you what I have done thus far.

the limit is as x -> 0

\frac{2^x - 2^0}{x - 0}

\frac{2^x - 1}{x}

So my question is what can I do to get x off the bottom.
 
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You've probably already proved that the limit x->0 of (e^x-1)/x=1. Try to use that.
 
Thanks, that helped.
 

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