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Using difference quotient I am trying to find f '(0) for 2^x. Basically my question is a questions of algebra but I will show you what I have done thus far.

the limit is as x -> 0

[tex]\frac{2^x - 2^0}{x - 0}[/tex]

[tex]\frac{2^x - 1}{x}[/tex]

So my question is what can I do to get x off the bottom.

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# Homework Help: Easy difference quotient question

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